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Here's a formula that should help solve this problem:

2/5 (2 divided by 5) {which equals 0.4, or 4/10 (four-tenths), which would equal to the problem to begin with, 2/5 (two-fifths).

Explanation:

All coins have two sides, Heads (1) and Tails (2). Your flipping the coin in the air 5 times. Two out of five tosses could either end up as one or the other. So, in retrospect, there is really a near infinite number of possible cominations the coin can land on.

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This looks like the answer to another question! The perils of merges?

There are 6 different combinations:

5T, 4T1H, 3T2H, 2T3H, 1T4H, 5H.

Note that these combinations do not have the same probabilities.

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Q: If a coin is flipped 5 times what are the different combinations you can get?
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