Here's a formula that should help solve this problem:
2/5 (2 divided by 5) {which equals 0.4, or 4/10 (four-tenths), which would equal to the problem to begin with, 2/5 (two-fifths).
Explanation:
All coins have two sides, Heads (1) and Tails (2). Your flipping the coin in the air 5 times. Two out of five tosses could either end up as one or the other. So, in retrospect, there is really a near infinite number of possible cominations the coin can land on.
* * * * *
This looks like the answer to another question! The perils of merges?
There are 6 different combinations:
5T, 4T1H, 3T2H, 2T3H, 1T4H, 5H.
Note that these combinations do not have the same probabilities.
The probability is 1. I have flipped a coin a lot more than 7 times.
Roughly half of the time, so about 350 times.
7/8
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375
Four outcomes, three combinations.
HeadsTailsTailsTailsHeadsTailsHeads
suppose you flipped a coin 100 times you might have flipped heads 50 time and tails 50 times
The probability is 1. I have flipped a coin a lot more than 7 times.
yes the coin is biased because it turned to heads 36 times.
1 and a half
Roughly half of the time, so about 350 times.
48
25%
30 maybe but i say 35 or 31
7/8
The possible outcomes of a coin that is flipped are heads or tails.
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375