HeadsTailsTailsTailsHeadsTailsHeads
16 outcomes
If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.
16
There are 25 = 32 possible outcomes.
the outcomes are 50:50.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
HeadsTailsTailsTailsHeadsTailsHeads
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
16 outcomes
If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.
16
Should be 16 possibilities: Coin on heads + 8 possibilities on die; Coin on tails + 8 possibilities on die = 16 total possibilities.
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
There are 25 = 32 possible outcomes.
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are 26 = 64 possible outcomes.