It is 1/6*1/6 = 1/36.
That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.
Assuming that the colors are balanced, the probability is 1 in 5.
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
Since there are 6 numbers on a die (1-6), then the probability of rolling a 5 would be 1 out of 6.
Since the numbers (number of dots) on normal dice only go from 1 - 6, then I would think the probability of getting the number 100 is zero.
That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.
The answer depends on how many sides the spinner has.
Assuming that the colors are balanced, the probability is 1 in 5.
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
It is 0.5
Well it would really depend on how many sections there are in the spinner and how many 3's and 5's there are.
There are 2 numbers less than 3, so the probability in this case is 2 in 8, or 1 in 4. There are 3 numbers greater than 5, so the probability in this case is 3 in 8. There are 5 numbers less than 3 or greater than 5, so the probability in this case is 5 in 8.
The total possibilities are listed below as pairs: (1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (2,4) (3,1) (3,2) (3,3) (3,4) (4,1) (4,2) (4,3) (4,4) The bold pairs in above list are the one's whose product would be 4. Thus, the probability would be: P = 3/16
2 numbers. few probabilities. Lets see. Number 1 probability: if your given numbers are this for example, 2 and 7. What is the probability of picking out 7? the Numerator is how many of that number is in the group. They are asking for 7? so how many 7's are in the group? 1. Then the denominator is how many numbers are in the group. There are 2 numbers in the group. so the probability of picking out a 7 would be 1/2. get it? if there were two 7's, then the probability would be 2/2 or 1. I hope I helped.
Get the spinner and have 4 sections, 3 with score and 1 with miss. Whichever one it lands on is the outcome. However, this is only purely theoretical as football/ soccer is played on grass and not with a spinner.
Probability = number_of_ways_of_success / total_number_if_outcomes As a cube has 6 faces and you have only specified that it has five numbers (1-5), one of those numbers must be repeated, thus the probability of rolling a 5 depends upon whether there is one or two sides bearing a 5: If there is only 1 side bearing a 5, then it is 1/6 If there are 2 sides bearing a 5, then it is 2/6 = 1/3 If you meant a five sided solid, then there is no such regular solid and some face(s) would be biased to appear and it would depend upon which face has the 5. However, an icosahedron has 20 faces and the numbers 1-5 could be repeated 4 times each, meaning that the probability of rolling a 5 would be 4/20 = 1/5. If you had a regular pentagonal spinner, with each digit corresponding to an edge, then the probability of spinning a 5 would be 1/5. If you mean a standard die: a cube with six sides numbers 1-6 (and the 1-5 was a typographical error), then the probability is 1/6.
If the data is ordered, that would be the median. If organised according to probability, that would be the mean.