1/3
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
120
Hector has a bag with 6 coins: 2 quarters, 1 nickel and 3 dimes.The probability of randomly pulling a dime is: 3/6 = 1/2 = 0.50 = 50.0%Hector's chance of pulling a quarter out of the bag is 2/6 = 1/3.
The probability of drawing a white marble is .46
0.4
It is incalculable.
4/10
well the dimes account for about 1/4 of the amount so about 25%
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
120
1/35 or 2.86%
28
A laundry bag contains 160 black socks and 300 red socks. 1940 black socks must be added so that the probability of choosing a black sock is 7 of 8.
We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.
Hector has a bag with 6 coins: 2 quarters, 1 nickel and 3 dimes.The probability of randomly pulling a dime is: 3/6 = 1/2 = 0.50 = 50.0%Hector's chance of pulling a quarter out of the bag is 2/6 = 1/3.
If you reach into the bag, grasp, and withdraw your hand, the probability of pulling something out is about 100%.
Now the 2 bags contain a total of 6 dimes and 5 quarters, which is a total of 11 coins. Therefore, the probability of getting a quarter is (5/11) which is about 0.4545.... or 45.45% as the case may be. Hope this helps