When two coins are tossed, the results that can be achieved are HH, HT, TH, and TT where H represents a heads and T represents a tails. The probability of getting two heads is 1/4, and by symmetry the probability of getting two tails is 1/4. The probability of getting one heads and one tails in some order is 1/2 which is the most likely outcome.
Who is asking these questions anyway? Why cant we insert E for edge in the equation. Would a coin NEVER land on its' edge? How about in the water? Didn't George attempt to throw a dollar across the Delaware River? Did we ever hear if he made it? If it landed in the muddy bank, odds are better it landed on its edge. If someone keeps asking these vague questions, no one can ever give a definitive answer unless a lot of stupid assumptions are made. Now they won't be stupid if you first list them. Now, let's see your list.
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When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.
Heads ( H ) Tails ( T ) HH , TT , HT , TH
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
It is the event that one of the two coins lands showing tails and the other shows heads.
Sample space for two coins tossed is: HH HT TH TT Therefore at most one head is HT TH TT or 3/4 or 0.75.