239, since each of the 39 numbers may or may not be included in the result set. If we exclude the option that no number is chosen, the answer is 239-1.
Just 1.
4 of them. In a combination the order of the numbers does not matter.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
26x26x26x10x10x10 = 17,576,000
252 combinations, :)
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
Formula: nPr where n is the number of things to choose from and you choose r of them 17P3 = 17!/ (17-3)! = 4080
There are 167960 combinations.
86,450
Just 1.
There are: 17C5 = 6188
10,000
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
56 combinations. :)
4582
9