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Q: In 25712 what does digit 5 stand for?
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How many 4 digit codes can you get from the numbers 1 2 3 4 and 5?

For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.


How many different 3 digit number can be formed from 13579 if there's repetition?

As there are 5 different digits, allowing for repetition of a digit, the first digit can be any of the 5, and for each of these, the second can be any of the 5, and so for the third, making: 5 x 5 x 5 = 125 different 3-digit numbers.


How many positive four digit integers have 1 as their first digit and 2 or 5 as their last digit?

There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.


How many 5 digit combinations for numbers 1- 25?

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.


How do you round off to leave one nonzero digit of 6 592?

Look at the first digit after the first non-zero digit;if it is 5 or more, add one to the first digit, otherwise keep the first digit as it is;replace all the digits after the first digit by 0s.6592:First digit is 6, first digit after it is 5is 5 greater than or equal to 5 - yes, so add 1 to the first digit: 6 + 1 = 7replace the 592 by 000, to give 7000