So I took the worksheet and found that in Punnett Square A (if you have the same worksheet) It has the pairs BB, Bb, Bb, and bb. B= black and b= white. The probablility of a black guinea pig is likely and white is unlikely since there is only 1 trait with 2 recessive alleles.
If you want to ask questions about something that is "shown", then I suggest that you make sure that there is something that is shown.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
To calculate the probability of drawing a black card and a 7 from a standard deck of 52 cards, we first determine the total number of black cards and the number of 7s in the deck. There are 26 black cards (13 spades and 13 clubs) and 4 sevens in the deck. The probability of drawing a black card and a 7 is calculated by multiplying the probability of drawing a black card (26/52) by the probability of drawing a 7 (4/52), resulting in a probability of (26/52) * (4/52) = 1/26 or approximately 0.0385.
The probability of picking a black ace in one random draw from a normal pack of playing cards is 1/26.
It is 3/13. The fact that the card is black makes no difference since the probability is the same for both colours.
depends on the two guinea pigs genotypes. could be anywhere from 75 to 100 percent.
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
The black guinea pig is likely heterozygous (Bb) for coat color, while the white guinea pig is homozygous recessive (bb). The black guinea pig passes on a black allele to all offspring, resulting in 4 black (Bb) and 2 white (bb) offspring.
A test cross with a homozygous recessive guinea pig (bb) would reveal the genotype of the black guinea pig. If all offspring are black, then the black guinea pig is most likely homozygous dominant (BB). If both black and white offspring are produced, then the black guinea pig is likely heterozygous (Bb).
no dont let them
In a monohybrid cross with black as dominant (B) and white as recessive (b), the probability of an offspring being black is 75% (3/4) and the probability of being white is 25% (1/4) according to the Punnett square ratios.
4 offsprings
Yes
The answer depends on how big the litter is: as the litter size increases the probability of one black fur increases. But as it gets larger still, the probability falls because two or more black furs become more probable.
Well you see black people are useless. Whoever made the black child is obviously an ape of some sort.
The black guinea pig is homozygous for the black coat color gene, while the albino guinea pig is homozygous for the albino gene. When the albino is crossed with a black guinea pig, all the offspring inherit the black coat color gene but show the dominant black phenotype. When the albino is crossed with a second black guinea pig that is heterozygous for the gene, it leads to a 3:1 ratio of black to albino offspring due to the inheritance of the albino gene.
100% because BB is dominant over bb and all the crosses make Bb