Only if you're counting order. If you call a head then a tail different from a tail and then a head then there are 8 outcomes from the coins; otherwise there are only 4. And clearly a number cube can have anywhere from 1 to 6 outcomes, depending on whether the same number appears multiple times.
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
There are 23 = 8 possible outcomes.
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT
Tossing two coins doesn't have a probability, but the events or outcomes of tossing two coins is easy to calculate. Calling the outcomes head (H)or tails (T), the set of outcomes is: HH, HT, TH and TT as follows: 2 heads = (1/2) * (1/2) = 1/4 1 head and 1 tail, can be heads on first coin tails on second, or just the opposite, there's two possible events: (1/2)*(1/2) + (1/2)*(1/2) = 1/2 2 tails = same probability as two heads = 1/4
By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
There are 23 = 8 possible outcomes.
4
For each of the coins, in order, you have two possible outcomes so that there are 2*2*2*2 = 16 outcomes in all.
There are 1024 different outcomes, so too many to list.
No. The number of outcomes is 24 which is 16, not 64. Furthermore, probability is a number that is associated with an outcome and is a number in the range [0, 1]. Neither 16 nor 64 are number in the relevant range.
The sample space consists of the following four outcomes: TT, TH, HT, HH
It is used for lots of things such as finding out the total possible outcomes of tossing coins. You find the line that corresponds with how many coins you toss and add all the numbers in that line to get the number of possible outcomes also you can use it to find combinations and permutations and triangular numbers
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT
three heads two head, one tails one heads, two tails three tails
The total number of outcomes is 2^5 = 32.
Tossing two coins doesn't have a probability, but the events or outcomes of tossing two coins is easy to calculate. Calling the outcomes head (H)or tails (T), the set of outcomes is: HH, HT, TH and TT as follows: 2 heads = (1/2) * (1/2) = 1/4 1 head and 1 tail, can be heads on first coin tails on second, or just the opposite, there's two possible events: (1/2)*(1/2) + (1/2)*(1/2) = 1/2 2 tails = same probability as two heads = 1/4