Try 5/16 x 4/15 x 3/14 = 1/56 = 0.010178571
What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)
The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25
This is a law of addition probability which states that the probability of A or B equals the probability of A plus the probability of B minus the probability of A and B. Written in mathematical terms, the equation is: P(AorB) = P(A) + P(B) - P(AnB) where P(AnB) = 0 (since you can not pull out a green and black ball at the same time). Let P(A) = Probability of drawing the green ball & let P(B) = Probability of drawing the black ball. Total outcomes is 17. So, P(A) = 4/17 & P(B) = 6/17. Therefore P(green or black) = 4/17 + 6/17 = 10/17.
3/16
It is 1248/57120 = 13/595 = 0.0218 approx.
25
Total number of marbles in the bag = 6 + 19 + 5 + 19 + 17 = 66Number of yellow ones = 19If drawing perfectly randomly, then the probability of pulling a yellow one = 19/66 = 28.8% (rounded)
25%
What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)
The probability for most of the same colours is most likely green. One of each can be one of each, but there is a small chance you will get more red and yellow than green.
5/15 = 1/3 = 33 and 1/3 percent
There are 8 marbles that aren't black, out of a total of 12 marbles, so the probability is 8/12 or 2/3.
No comment
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25
About a 74% estimated probability of green,
The probability is 0.56