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The probability of heads on each of the coins is 1/2 or 0.50, and the die (we will assume a fair die, numbered 1 to 6) coming up 4 is 1/6. So we have: 1/2 x 1/2 x 1/6 = 1/24 = 0.04167 or approximately 4.2% chance of these three events occurring.

Q: Two nickels are tossed and a number cube is rolled what is the probability that you land on 2 heads and roll a 4?

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9/2

These are independent one has no bearing on the other

With one toss of a coin, there can be at most 1 head. So the probability of 4 or more heads is very definitely 0.

The probability is 90/216 = 5/12

A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.

Related questions

If the coin is tossed and the die rolled sufficiently many times then the probability is 1: the event is a certainty.For just one toss and roll, the probability is 0.25

The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.

Coins do not have numbers, there is only the probability of heads or tails.

9/2

These are independent one has no bearing on the other

These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12

With one toss of a coin, there can be at most 1 head. So the probability of 4 or more heads is very definitely 0.

The probability that the die tossed will land on a number that is smaller than 5 is 4/6 or 2/3. Smaller than 5 is 1 - 4 and 6 is the sample space.

The probability is 90/216 = 5/12

A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.

The probability is 1/16.

1/6