3, 6, 9, 12, 15
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To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
Multiples of 6 are numbers in the 6 times table. So the first 5 multiples of 6 are 6, 12, 18, 24 and 30.
12 is the first 24 is second and the third is 36
STOP - This seems to be a homework assignment.I strongly suggest you try to do it first, so that you gain the value of the lesson.The prime factors of 4725 are 3, 3, 3, 5, 5, and 7.Combining these in all of their combinations, along with 1 which is always a divisor, the divisors of 4725 are ...1 (1)3 (3)5 (5)7 (7)9 (3 3)15 (3 5)21 (3 7)25 (5 5)27 (3 3 3)35 (5 7)45 (3 3 5)63 (3 3 7)75 (3 5 5)105 (3 5 7)135 (3 3 3 5)175 (5 5 7)189 (3 3 3 7)225 (3 3 5 5)315 (3 3 5 7)525 (3 5 5 7)675 (3 3 3 5 5)945 (3 3 3 5 7)1575 (3 3 5 5 7)4725 (3 3 3 5 5 7)... so, there are 24.
For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.