2, 4, 6, 8, 10
3, 6, 9, 12, 15
12 is the first 24 is second and the third is 36
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
{3, 6, 9, 12, 15, 18, 21 ...} It is an infinite set
The first five nonzero multiples of 6 are 6, 12, 18, 24 and 30.
The first five multiples of 6 are 6, 12, 18, 24 and 30. For them to be common, they need to be compared to another set of multiples.
30, 60, 90, 120, 150
0, 2, 4, 6, 8.0,2,4,6,8 are the first five multiples of 2
30,60,90,120,150
The common multiples of 5 and 6 are the multiples of their lowest common multiple (which is 30), so there are infinitely many common multiples of 5 and 6. The first five are: 30, 60, 90, 120, 150.
6, 12, 18, 24, 30
First three common multiples of 5 and 6 are 30, 60 and 90.
Since the GCF of 5 and 6 is 1, their LCM is their product. The first five multiples of 30 are 30, 60, 90, 120, 150
6+12+18+24+30=90
1, 2, 3, 6, and 11
The five multiples of 201 are 201,402,604,806,and 1008.Those are the first five multiples of 201,I got it by multiplying 201 by what # I needed.