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Q: If there are three coins and each is flipped once how many possible outcomes are there?

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We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).

There are 23 = 8 possible outcomes.

The probability of flipping three tails with three coins is (1 in 2)3 or 1 in 8 or 0.125.

Three possible outcomes:WinLooseDraw

In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.

Related questions

We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).

There are 23 = 8 possible outcomes.

Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.

There are eight (8).

Eight of them.

There are three possibilities, Heads, Tails and stand on edge

9, you just have to multiply for problems like this

Number of possible outcomes with 4 coins = 2 x 2 x 2 x 2 = 16.Number of successes = 2. (Three heads or four heads)Probaility of success = 2/16 = 1/8 = 12.5 percent

Sample space: {hhh,hht,hth,htt,ttt,tth,tht,thh} 8 possible outcomes

It is 0.5

There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.

three heads two head, one tails one heads, two tails three tails

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