third you will back the 4 in 34 become a 0 and drop down the zero in your answer under the four under the line..
fourth you will ha vet to multiply 6 x 3 = 18 put the 8 beside the zero and put the one one the very top of the five.
fifth you multiply 5 x 3= 15 and write do the 15 beside the zero and you should get..........
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There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
Any number with 2 numbers in it is a 2. Example: 95 They are numbers 10 - 99.
2
By using the 3 digits of a number we can form 3 different two digit numbers. 3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3
If you want 4-digit numbers, there are 24 of them.