There are two problems in answering this question. The gender of children are not independent events and also, the probability of a boy is not half as is often assumed but nearer to 52% and it varies over time and between countries.
However, if you assume that the genders are independent and that the probability of either gender is 0.5 then the answer is 0.875
Doesn't matter how many children they have - each time you have a child you have a 50:50 chance of either a girl or a boy.
You can calculate the probability that NONE of them is a boy - that's 1/2 x 1/2 x 1/2. The complement of that is the answer to your question - so 1 - 1/8 = 7/8.
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.If you believe that the children's genders are not independent then you would need to get empirical evidence from all families with four or more children in which the first three children were girls. If there are g families in which the fourth is a girl and b where the fourth is a boy then the required probability is b/(g+b).However, if you assume that the children's genders are independent events then, given that the probability of a boy is approx 0.52, the probability of the fourth child is a boy is 0.52
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of three out of three being girls is 0.1127.
50/50
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
Assuming that children of either gender are equally likely, the answer is (1/2)3 = 1/8
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.If you believe that the children's genders are not independent then you would need to get empirical evidence from all families with four or more children in which the first three children were girls. If there are g families in which the fourth is a girl and b where the fourth is a boy then the required probability is b/(g+b).However, if you assume that the children's genders are independent events then, given that the probability of a boy is approx 0.52, the probability of the fourth child is a boy is 0.52
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability that all three children are boys is approx 0.1381
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of three out of three being girls is 0.1127.
50/50
there is a 50% chance that two of them will be girls
With one roll of three dice, the probability is 7/8.
1/4
The probability that three F2 seeds chosen from Mendel's study group will have at least one yellow seed is 63/64. It would be very rare to get three green seeds.