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When a coin is tossed 9 times in a row what is the probability that heads comes up 9 times?
It is (1/2)9 = 1/512
A coin is tossed 9 times. What is the probability of getting exactly 4 heads.... What is the probability of getting at most 2 heads?
The number of trials: n = 9, the number of success: r = 4. The probability of success: P(H) = 1/2, the probability of failure: P(T) = 1/2. P(exactly 4 heads in 9 tosses) = 9C4 x (1/2)^5 x (1/2)^4 = 126(1/2)^9 = 0.246 P(at most 2 heads) = P(none heads) + P( 1 head) + P(2 heads) = 9C0[(1/2)^9][(1/2)^0] + 9C1[(1/2)^8][(1/2)^1] + 9C2[(1/2)^7][(1/2)^2] = 1(1/2)^9 + 9(1/2)^9 + 36(1/2)^9 = (1 + 9 + 36)(1/2)^9 = 46(1/2)^9 = 0.09
A fair coin is tossed 9 times What is the probability that At least two heads appear?
well, it will have 6 times of the greater chance.
Three fair coins are tossed at the same time What is the probability that one of the coins will show heads and the other two will show tails?
2/9
If a coin is tossed for 30 times what is the probability of having no heads?
No heads means that every toss lands tails. (0.5)30= 9.3 x 10-10 Note that 109 = 1 trillion, so the probability can be stated this event is likely to occur about 9 times in 10 trillion tosses.
If you flip a coin and get 9 heads in a row what is the probability of getting heads on the next flip?
50%.
When a coin is tossed 9 times in a row what is the probability that heads comes up 9 times?
It is (1/2)9 = 1/512
What is the probability of getting heads from a coin 9 times in a row?
If you continue tossing the coin forever, it is effectively a certainty. So probability = 1 If you toss it only 9 times, it is (1/2)9 = 1/512 = 0.00195 (approx)
What is the probablity that the sequence will be heads-heads-heads if you toss a coin 3 times?
the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.
What is probability of throwing either 7 or more than 10 with two dice?
It is 9/36 = 1/4
A coin is tossed 9 times. What is the probability of getting exactly 4 heads.... What is the probability of getting at most 2 heads?
The number of trials: n = 9, the number of success: r = 4. The probability of success: P(H) = 1/2, the probability of failure: P(T) = 1/2. P(exactly 4 heads in 9 tosses) = 9C4 x (1/2)^5 x (1/2)^4 = 126(1/2)^9 = 0.246 P(at most 2 heads) = P(none heads) + P( 1 head) + P(2 heads) = 9C0[(1/2)^9][(1/2)^0] + 9C1[(1/2)^8][(1/2)^1] + 9C2[(1/2)^7][(1/2)^2] = 1(1/2)^9 + 9(1/2)^9 + 36(1/2)^9 = (1 + 9 + 36)(1/2)^9 = 46(1/2)^9 = 0.09
Fair coin is tossed 11 times What is the probability that a Exactly 9 heads appear b At least two heads appear c At most 8 heads appear?
Prob(Exactly 9 Heads) = 0.0269 Prob(At least 2 Heads) = 0.0327 Prob(At most 8 Heads) = 0.9673
What is the probability of throwing a 3 or 6 if you role two dice at once?
In this case, you should first calculate the probability of NOT rolling either a 3 or a 6. For one die, this probability is 4/6 = 2/3. For two dice, this probability is 2/3 x 2/3 = 4/9. Therefore, the probability that you DO get a 3 or a 6 is 1 - 4/9 = 5/9.
What is the probability of tossing a coin 9 times and getting at least one tail?
The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%
A fair coin is tossed 9 times What is the probability that At least two heads appear?
well, it will have 6 times of the greater chance.
A group of 5 women and 4 men are placed at random in 9 chairs in a row what is the probability that the result is an alternate seating arrangement?
(4!*5!)/9! = .0079
10 coins are tossed once .The probalilty of getting exactly eight heads is?
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
