Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.
This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381
Assuming that the chance of a woman giving birth to a boy or a girl is the same (in reality there's about 105 boys born for every 100 girls) then the probability of 22 of the same gender births *in a row* is: P=(0.5)^22=0.0000002384 or 1 in 4,194,304 It depends on the "when" of the question. If you point at a childless woman, and say "She will give birth to 22 children. What is the likelyhood that they will all be girls?" In that case the probability will be one in two-to-the-twenty-second. Pretty long odds. BUT, if you point at a woman with twenty one children, and ask "What are the odds that the next one will be a girl?" Then the answer is one in two. Make sense?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
The probably of four girls in a family with four children is 1/16. I got this answer because: Probability of a girl is 1/2 and to get all girls you would multiply it by 1/2 for the rest of the girls.
there is a 50% chance that two of them will be girls
Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.
It depends on the couples' genes. Also, at present the probability of a girls is approx 0.48
0.48
3 out of 7
It is not possible to give a proper answer to the question for two main reasons. The first reason is that the probability of boys and girls are not equal. The global probability, at birth is 0.517 for boys and 0.483 for girls. Second, the children's genders are not independent events. Third, the gender ratios change with the parents' (mother's) age. If you choose to ignore all these facts, then the probability is (1/2)4 = 1/16
..Not usually. But it may happen to some girls.
it is either the baby was forming in an unusual way and it comes out different,, the pain ANSWER complications from the birth, infections, blood loss, there are many reasons for which a woman could die giving birth
This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381
Assuming that children of either gender are equally likely, the answer is (1/2)3 = 1/8
Assuming that the chance of a woman giving birth to a boy or a girl is the same (in reality there's about 105 boys born for every 100 girls) then the probability of 22 of the same gender births *in a row* is: P=(0.5)^22=0.0000002384 or 1 in 4,194,304 It depends on the "when" of the question. If you point at a childless woman, and say "She will give birth to 22 children. What is the likelyhood that they will all be girls?" In that case the probability will be one in two-to-the-twenty-second. Pretty long odds. BUT, if you point at a woman with twenty one children, and ask "What are the odds that the next one will be a girl?" Then the answer is one in two. Make sense?
The probability is 2 - 6
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.