If the choice is unbiased, the change is 14/(10+14).
If the chooser prefers choosing boys, the probability is 0.
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
1-30
3-7
14/33
12/27 reduces to 4/9 numerator = the number of acceptable outcomes denominator = total number of outcomes (12 boys + 15 girls)
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
1
4/8 x 3/5
The probability of choosing 2 girls at random from group of 25 students of which10 are girls and 15 are boys is:P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
The probability is 15/25 = 3/5
1-30
3-7
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
To find the probability that a girl will be chosen as president, you can use the formula for probability: ( P(\text{girl}) = \frac{\text{number of girls}}{\text{total number of students}} ). There are 9 girls and 12 boys, making a total of 21 students. Thus, the probability is ( P(\text{girl}) = \frac{9}{21} = \frac{3}{7} ).
The probability is 15/25 = 3/5
1/35
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!