10 out of 36 or approx 27.78 % (see below for explanation)
If you roll two dice the probability of rolling two on the first OR the second (but not both) is the probability of rolling a two (at least one time) on two throws minus probability of rolling two on both.
Probability of a two coming up at least once is 11 out of 36 (11/36)
You cannot just add 1/6 + 1/6 = 1/3
If that were true then you could throw it six times and get a probability of [1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1] meaning it's guaranteed to happen.
So to get the 11/36, you can create a chart:
11 21 31 41 51 61
12 22 32 42 52 62
13 23 33 43 53 63
14 24 34 44 54 64
15 25 35 45 55 65
16 26 36 46 56 66
And see that it happens 11 out of the possible 36 times, or use a formula.
1 - (probability it won't happen on one try)^(number of tries)
probability it won't happen on one try: 1 - 1/6 = 5/6
So (5/6)^2 = 25/36. Then 1 - 25/36 = 11/36.
Now the chance you get a two on both throws is 1/36, so subtract 11/36 - 1/36 = 10/36. (this can be seen on the chart as 10 positions where there are only one occurrence of two)
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
The probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die is 1 in 12. The two die are sequentially unrelated, so you can consider them separately. The probability of rolling an odd number is 3 in 6, or 1 in 2. The probability of rolling a 1 is 1 in 6. Multiply the two probabilities together and you get 3 in 36, or 1 in 12.
2/12 or 1/6
The probability of not rolling a 6 is 5/6.
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
The probability is 1 out of 36, or about 3%, I think.
1/6 on the first roll, and 1/6 of rolling a six on the second roll. Overall, the chances of you rolling a 5 on the first and a six on the second is 1/3.
The probability of throwing just one one with two dice can be calculated by considering the different ways it can occur. There are two ways to get one one: rolling a one on the first die and any number on the second die, or rolling any number on the first die and a one on the second die. There are a total of 36 possible outcomes when rolling two dice, so the probability is 2/36, which simplifies to 1/18.
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
The probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die is 1 in 12. The two die are sequentially unrelated, so you can consider them separately. The probability of rolling an odd number is 3 in 6, or 1 in 2. The probability of rolling a 1 is 1 in 6. Multiply the two probabilities together and you get 3 in 36, or 1 in 12.
Find aobability
The probability of rolling a 3 is 1/6. The probability of rolling a 6 is 1/6. There are two ways to roll a 3 and 6: roll 3 on the first die and 6 on the second or roll 6 on the first and 3 on the second. The probability of the first is 1/6 x 1/6 = 1/36. Likewise the probability of the second is 1/6 x 1/6 = 1/36. Combined you get 1/36 + 1/36 = 2/36 = 1/18
0.25 ( P = 0.5 each time)
2/12 or 1/6
The probability of not rolling a 6 is 5/6.