There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability 4 boys and 1 girl out of 5 children is 0.1724 approx.
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
50%, the Father's contribution decides the sex of a child.
1/12 =0.08333... ≈ 8.3%
if we assume that the probability for a girl being born is the same as a boy being born: (1/2)^6 = 0.015625 = 1.5625%
In a family with four children, the probability of having four boys is 1 in 16.
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
Since the probability of having a son is about 1/2, the probability of the first 4 children being boys is about (1/2)4.
Assuming the probability of having a boy is 1/2, and that the probabilities are independent: Probability of 1 girl and 12 boys = (1/2)13 * 13 = 0.001587..., which is around 1/630
3/8
There is only one girl out of 12 students so the probability that the girl is selected is 1/12.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of three boys and a girl is 0.2669.
50%, the Father's contribution decides the sex of a child.
1:1
1/12 =0.08333... ≈ 8.3%
if we assume that the probability for a girl being born is the same as a boy being born: (1/2)^6 = 0.015625 = 1.5625%
Assuming probability of having a boy is P(B) = 1/2, and of having a girl is P(G) = 1/2,the probability of having 3 boys for 4 kids (with out regard to the girl to be the first,second, third or fourth kid) is;P(3B1G) = 4C3 [P(B)]4 = 4 (1/2)4 = 0.250 = 25%The factor 4 comes because there are 4 possibilities for the order in which the girl cancome out.
In a family with four children, the probability of having four boys is 1 in 16.