1 out of 4. Regardless of what the first two children are, there is a 50/50 chance that each of the following two kids will fulfill the remaining two conditions
50%
50/50
Assuming that boys and girls are equally likely, it is 11/16.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
The answer depends on whether the children are picked at random. If they were selected from inside a girls' school the probability should be quite close to 0. Likewise, if the children were picked inside a boys' school. If six children are picked at random from a large group of children with an equal number of boys and girls, then the answer is 6C2*(1/2)6 = 15/32 = 0.47, approx.
50%
50/50
Assuming that boys and girls are equally likely, it is 11/16.
Since the probability of having a son is about 1/2, the probability of the first 4 children being boys is about (1/2)4.
Assuming that having boys and girls are equally likely, then the probability is 1/8. * * * * * You also need to assume that the children's genders are independent. They are NOT and depend on the parents' ages and genes.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
Probability
It is not possible to give a proper answer to the question for two main reasons. The first reason is that the probability of boys and girls are not equal. The global probability, at birth is 0.517 for boys and 0.483 for girls. Second, the children's genders are not independent events. Third, the gender ratios change with the parents' (mother's) age. If you choose to ignore all these facts, then the probability is (1/2)4 = 1/16
The answer depends on whether the children are picked at random. If they were selected from inside a girls' school the probability should be quite close to 0. Likewise, if the children were picked inside a boys' school. If six children are picked at random from a large group of children with an equal number of boys and girls, then the answer is 6C2*(1/2)6 = 15/32 = 0.47, approx.
1/35
In a family with four children, the probability of having four boys is 1 in 16.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability 4 boys and 1 girl out of 5 children is 0.1724 approx.