Well, consider that there are 26 letters in the alphabet. 5 of these are vowels (a, e, i, o and u).
Therefore the probability is 5/26 - or 0.192307692.
This assumes, of course, that you are randomly picking a letter from the alphabet... or rather, that each letter occurs in equal proportion within a larger text.
This assumes the English alphabet. In other alphabets from other languages, there may be a different quantity of vowels and a different quantity of consonants (or possibly other letters all together).
In writing, however, it is not the case that each letter appears in equal proportion. In a typical written document, for example, vowels make up about 38% of a text, on average. But it depends on a particular text, too, it may vary a little.
Of course, it matters which language you draw a text from. Those languages which use the exact same alphabet as in English dont necessarily have the same distribution of vowels in text.
Normally 5/26 but if you count "y" as a vowel, 6/26 or 2/13.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
Probability is given as Desired Outcomes divided by total number of outcomes. For the probability of picking a vowel, desired outcomes are : a,e,i,o,u (5) Total no. of outcomes is the entire alphabet set from a to z (26) Hence, the required probabilty is 5/26
the answer is 1 out of 26
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
4/11
The probability that a letter picked at random is not a vowel depends on the set of letters you are choosing from. In the English alphabet, there are 21 consonants and 5 vowels, so the probability of picking a consonant is 21/26 or approximately 0.808.
Q. A letter is chosen at random from the word STATistician.What is the probability that it is a vowel?What is the probability that it is T.
Normally 5/26 but if you count "y" as a vowel, 6/26 or 2/13.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
Probability is given as Desired Outcomes divided by total number of outcomes. For the probability of picking a vowel, desired outcomes are : a,e,i,o,u (5) Total no. of outcomes is the entire alphabet set from a to z (26) Hence, the required probabilty is 5/26
if you only consider the vowels to be aeiou, then the answer is that you have a 5 out of 26 (or .19%) chance.
The probability for a single random choice, is 6/13.
sample space=13 no of possible outcomes (vowel)=5/13 no of possible outcomes (consonant)=7/13
the answer is 1 out of 26
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%