Well, consider that there are 26 letters in the alphabet. 5 of these are vowels (a, e, i, o and u).
Therefore the probability is 5/26 - or 0.192307692.
This assumes, of course, that you are randomly picking a letter from the alphabet... or rather, that each letter occurs in equal proportion within a larger text.
This assumes the English alphabet. In other alphabets from other languages, there may be a different quantity of vowels and a different quantity of consonants (or possibly other letters all together).
In writing, however, it is not the case that each letter appears in equal proportion. In a typical written document, for example, vowels make up about 38% of a text, on average. But it depends on a particular text, too, it may vary a little.
Of course, it matters which language you draw a text from. Those languages which use the exact same alphabet as in English dont necessarily have the same distribution of vowels in text.
Normally 5/26 but if you count "y" as a vowel, 6/26 or 2/13.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
Probability is given as Desired Outcomes divided by total number of outcomes. For the probability of picking a vowel, desired outcomes are : a,e,i,o,u (5) Total no. of outcomes is the entire alphabet set from a to z (26) Hence, the required probabilty is 5/26
the answer is 1 out of 26
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
4/11
To work out probability you have to know the number of possible options, and how many of those options meet the criteria. In this case there are 26 possible options (all the letters) and 21 that meet the criteria (21 non-vowels). The probability is the number that match divided by the total number possible. In this case it would be 21/26. This comes out to approximately 0.80769. Thus the probability that a letter picked at random is not a vowel is 0.80769
Q. A letter is chosen at random from the word STATistician.What is the probability that it is a vowel?What is the probability that it is T.
Normally 5/26 but if you count "y" as a vowel, 6/26 or 2/13.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
Probability is given as Desired Outcomes divided by total number of outcomes. For the probability of picking a vowel, desired outcomes are : a,e,i,o,u (5) Total no. of outcomes is the entire alphabet set from a to z (26) Hence, the required probabilty is 5/26
if you only consider the vowels to be aeiou, then the answer is that you have a 5 out of 26 (or .19%) chance.
The probability for a single random choice, is 6/13.
sample space=13 no of possible outcomes (vowel)=5/13 no of possible outcomes (consonant)=7/13
the answer is 1 out of 26
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%