21/36 = 7/12
Assuming the numbers on the die are 1, 2, 3 and 4, the probability is 1.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
assuming we are talking about standard dice here (six sided, numbered 1-6) then the probability of obtaining a result other than 12 when a single die is tossed is 100%. There is no way to roll a 12 after 1 toss of 1 die, therefore the chance of getting anything other than 12 is guaranteed
The probability of rolling a particular face in a 12 sided die is 1 in 12, or about 0.0833.
It is 0.375
1 / n!
Assuming the numbers are 1-6, the probability is 0.
It depends on the numbers on the 4 sided die. I don't believe that is a recognised standard.
Assuming the numbers on the die are 1, 2, 3 and 4, the probability is 1.
Each die toss is independent; so the probability of 4 on the fourth trial is still 1/6.
The probability of getting an even number on a six sided dice is 3 out of 6 or one half because the only even numbers are 2,4,6 (which are all even).
The answer depends on what numbers are on the faces of the dice.
There is always a 1 in 6 chance of rolling ANY number on a six-sided dice, as there are 6 numbers.
A standard six-sided die has 3 even numbers and 3 odd ones, so the probability of rolling either an odd or even number would be 50-50.
If the die is a regular octahedron, then the probability for each face is 1/8.
Even numbers: 2, 4, 6, the probability to get an ven number is 3/6 = 1/2 The probability to get 4 even number in a row is then (1/2)4 = 1/24 = 1 / 16 It is the same probability to get 4 odd numbers (1,3,5) in a row
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.