5 times.
When tossing 2 pennies there are 4 equiprobable outcomes or events with 1/4 of
probability for each to happen:
P(H,H) = 1/4
P(H,T) = 1/4
P(T,H) = 1/4
P(T,T) = 1/4
So if you toss 2 pennies 20 times, the "expected" number of times that 2 heads (H,H)
will come up is 1/4 of the 20 times, that is 5 times.
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A fair coin would be expected to land on heads 10 times on average.
A fair coin would be expected to land on heads 75 times.
Roughly half of the time, so about 350 times.
Expected number of heads is 1/4 * 32 or 8 heads.
This is a binomial probability distribution The probability of exactly 2 heads in 50 coin tosses of a fair coin is 1.08801856E-12. If you want to solve this for how many times 50 coin tosses it would take to equal 1 time for it to occur, take the reciprocal, which yields you would have to make 9.191019648E11 tosses of 50 times to get exactly 2 heads (this number is 919,101,964,800 or 919 billion times). If you assume 5 min for 50 tosses and 24 hr/day tossing the coin, it would take 8,743,360 years. That is the statistical analysis. As an engineer, looking at the above analysis, I would say it is almost impossible flipping the coin 50 times to get exactly 2 heads or I would not expect 2 heads on 50 coin tosses. So, to answer your question specifically, I would say none.