cos(x)=sin(x-tau/4)
tan(x)=sin(x)/cos(x)
sin(x)=tan(x)*cos(x)
cos(x)=tan(x-tau/4)*cos(x-tau/4)
you can see that we have some circular reasoning going on, so the best we can do is express it as a combination of sines and cotangents:
cos(x)=1/cot(x-tau/4)*sin(x-tau/2)
tau=2*pi
Cotangent is ' 1/tangent' or ' Cosine / Sine'.
Cotangent is 1 / tangent. Since tangent is sine / cosine, cotangent is cosine / sine.
sine, cosine, tangent, cosecant, secant and cotangent.
Sine, Cosine, Tangent, Cotangent, secant and cosecant
sine, cosine, tangent, cosecant, secant and cotangent.
Cotangent is ' 1/tangent' or ' Cosine / Sine'.
Cotangent is 1 / tangent. Since tangent is sine / cosine, cotangent is cosine / sine.
sin(x) = [1 + cot^2(x)]^-0.5
sine, cosine, tangent, cosecant, secant and cotangent.
Sine, Cosine, Tangent, Cotangent, secant and cosecant
The second quadrant (top left).
sine, cosine, tangent, cosecant, secant, cotangent.
Reciprocal of tangent is '1 /tangent' or ' Cosine / Sine '
No, it is not. To be correct, the expression requires parenthesis, which are missing.
Cot in trigonometry is the cotangent, which is cosine over sine, or x over y.
Sine, Cosine, Tangent, Cosecant, Secant, Cotangent.
Assuming that "secany" is meant to be secant, the answer is cosecant.