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Negatives cause no problem: log10x = -3 means x = 10-3 = 0.001 It doesn't make sense, though, to FIND the logarithm of a negative number: log10(-8) = ???? (unless you know about complex numbers . . . )

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16y ago

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For any logarithm

10^(-x) can be re-written as '1/10^(x)'.

NB Note the negatrive has gone.

So of x = 2

Them

1/10^(2) =

1/100 =

0.01

Or 10^(-2) = 0.01

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lenpollock

Lvl 16
2y ago
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  • log_2⁡x=-3
    
  •  x=2^(-3)
    
  •  x=1/8
    
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Q: How do you solve logarithms with a negative in front?
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