The inexact value of tan 330 is -0.577350, to six significant places. The exact value cannot be represented as a single number because it is a non terminating decimal. To represent it exactly, consider that tan x is sin x over cos x, and that sin 330 is -0.5 and cos 330 is square root of 0.75. As a result, the exact value of tan 330 is -0.5 divided by square root of 0.75.
tan u/2 = sin u/1+cos u
To find the value of ( \frac{19 \sin(50^\circ)}{\sin(40^\circ)} ), we can use the sine function values. Using the sine of complementary angles, ( \sin(50^\circ) = \cos(40^\circ) ). Therefore, ( \frac{19 \sin(50^\circ)}{\sin(40^\circ)} = \frac{19 \cos(40^\circ)}{\sin(40^\circ)} = 19 \cot(40^\circ) ). For an exact numerical value, you can compute ( 19 \cot(40^\circ) ) using a calculator.
0.34202014332566873304409961468226
The exact value is 0.5*sqrt(3)
The exact value of sin 22.5 is 0.382683432
what is the value of sin 75 degree
The exact value is 0.40673664.
sin(405) = square root of 2 divided by 2 which is about 0.7071067812
sin 480° is equal to sin 60°, which is sqrt(3)/2 or approximately 0.866.
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
SQRT(3)/4 - 1/4
1/squareroot2 ummm, yes, but be aware that square root 2 is an irrational number that has *no* exact value. So your question cannot be answered in the terms you asked it. You can use a calculator to get as much precision as you want, but never an *exact* answer.
The inexact value of tan 330 is -0.577350, to six significant places. The exact value cannot be represented as a single number because it is a non terminating decimal. To represent it exactly, consider that tan x is sin x over cos x, and that sin 330 is -0.5 and cos 330 is square root of 0.75. As a result, the exact value of tan 330 is -0.5 divided by square root of 0.75.
The value of sin(1) is 0.
The exact value of (\sin 165^\circ) can be calculated using the sine subtraction formula. Since (165^\circ = 180^\circ - 15^\circ), we have: [ \sin 165^\circ = \sin(180^\circ - 15^\circ) = \sin 15^\circ ] The value of (\sin 15^\circ) can be derived from the formula (\sin(45^\circ - 30^\circ)), which gives: [ \sin 15^\circ = \sin 45^\circ \cos 30^\circ - \cos 45^\circ \sin 30^\circ = \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2} = \frac{\sqrt{6} - \sqrt{2}}{4} ] Thus, (\sin 165^\circ = \frac{\sqrt{6} - \sqrt{2}}{4}).
tan u/2 = sin u/1+cos u