Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared
If cos B is 5/13, find sin B, tan B, sec B, and cot B?sin= y/r= 12/13cos= x/r= 5/13tan= y/x= 12/5csc= r/y= 13/12sec= r/x= 13/5cot= x/y= 5/12x2+y2=r2
add 5 + 13 + 12 and divide by 3
13 remainder 5
13
It is: cos^-1(12/13) = 22.61986495 degrees
The answer depends on which of the three angles 'a' is!
It is about 67 degrees
sin = -12/13 cos = 5/12 tan = -5/12 cosec = -13/12 sec = 12/5 cotan = -12/5
The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees
5/13 = 0.3846 (to 4 dp)
Writing x instead of theta, cos2x = 1 - (12/13)2 = 1 - 144/169 = 25/169 = (5/13)2 So cos(x) = ± 5/13 so that x = cos-1(5/13) or cos-1(-5/13) And then, depending on the range of x, you have solutions for x. A calculator will only give you the principal solutions, though.
If you mean 5 by 12 by 13 then they will form a right angle triangle
4/5
If the right angle is at A then SA = 5 mm.
Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared
You have not indicated which side the angle is opposite of. Can us law of cosines then by calling sides c and a. b^2 = a^2 + c^2 - 2(a)(c) cos(B) I would arbitrarily have to assign values you have not given me.