The answer depends on which of the three angles 'a' is!
The best way to answer this question is with the angle addition formulas. Sin(a + b) = sin(a)cos(b) + cos(a)sin(b) and cos(a + b) = cos(a)cos(b) - sin(a)sin(b). If you compute this repeatedly until you get sin(3x)cos(4x) = 3sin(x) - 28sin^3(x) + 56sin^5(x) - 32sin^7(x).
sin^5 2x = 1/8 sin2x (cos(8x) - 4 cos(4x)+3)
5 dgs
It is down to trigonometry. You have two parts of a triangle, so you are looking for the length of the last line. As the man turned right, there will be a right angle in the triangle. As we have two sides, the 12m and 5m, using Pythagoras theorem we can work out the length of the last side. The square of the hypotenuse is equal to the square of the other two sides. 12 x 12 = 144. 5 x 5 = 25. 144 + 25 = 169. 13 x 13 = 169. So the length of the other side is 13.
It is: cos^-1(12/13) = 22.61986495 degrees
The answer depends on which of the three angles 'a' is!
It is about 67 degrees
It is: cos = adj/hyp and the acute angles for the given right angle triangle are 67.38 degrees and 22.62 degrees
sin = -12/13 cos = 5/12 tan = -5/12 cosec = -13/12 sec = 12/5 cotan = -12/5
The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees
5/13 = 0.3846 (to 4 dp)
Writing x instead of theta, cos2x = 1 - (12/13)2 = 1 - 144/169 = 25/169 = (5/13)2 So cos(x) = ± 5/13 so that x = cos-1(5/13) or cos-1(-5/13) And then, depending on the range of x, you have solutions for x. A calculator will only give you the principal solutions, though.
If you mean 5 by 12 by 13 then they will form a right angle triangle
4/5
If the right angle is at A then SA = 5 mm.
Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared