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What is the sin of angle B if the angles are 5 12 and 13?

This is a classic Pythagorean triangle. Although you have given the side lengths, you have NOT given a letter to correspond , with the given side. However, Let 12 be the adjacentr side (base) Let '5' be the opposite side ( perpendicular ) Let '13' by the hypotenuse. Sin(Angle) = opposite / hypotenuse = 5/13 Angle = Sin^(-1) 5/13 = 22.619... degrees. NB This is the angle between the hypotenuse and the base(adjacent) Now 'swopping' things around , we take the angle between the hypotenuse and the perpendicular (opposite) . This now becomes perpendicular(adjacent) and the base becomes the opposite. Hence Sin(angle) = 12/13 Angle = Sin^(-1) 12/13 = 67.380.... degrees. The angle at the 'top' of the triangle. Verification. ' 90 + 67.380... + 22.619... = 180 ( allow for calculator decimals).


What is the cos of angle B 5 13 12?

To find the cosine of angle B given the sides of a triangle, you typically use the cosine rule or the relationship between the sides. However, the values "5," "13," and "12" seem to refer to the lengths of the sides of a triangle. If these correspond to a triangle with sides a = 5, b = 12, and c = 13, you can use the cosine rule: ( \cos(B) = \frac{a^2 + c^2 - b^2}{2ac} ). Plugging in the values, ( \cos(B) = \frac{5^2 + 13^2 - 12^2}{2 \cdot 5 \cdot 13} = \frac{25 + 169 - 144}{130} = \frac{50}{130} ), which simplifies to ( \cos(B) = \frac{5}{13} ).


When a man walks 5m towards east and turns right and moves 12m the magnitude of his displacement is 13m how?

Pythagoras. The right turn is assumed to be 90 degrees, and moving southwards. This forms the two shorter sides on a right angled triangle. They applying Pythagoras. h^)2) = 5^(2) + 12^(2) h^(2) = 25 + 144 h^(2) = 169 Don't forget to 'square root' both sides!!!! Hence h = sqrt(169) = 13 . This is a classic Pythagorean triangle.


What is the cos of angle 'a' with the measurements 5 13 12?

Use Cosine Rule a^(2) = b^(2) + c^(2) - 2bcCosA Algebrically rearrange CosA = [a^(2) - b^(2) - c^(2)] / -2bc Substitute CosA = [13^(2) - 12^(2) - 5^(2)# / -2(12)(5) CosA = [ 169 - 144 - 25] / -120 Cos)A) = [0] / -120 CosA = 0 A = 90 degrees (the right angle opposite the hypotenuse)/ However, If 'A' is the angle between '12' & '13' then 'a' is the side '5' Hence (Notice the rearrangement of the numerical values). CosA = [5^(2) - 12^(2) - 13^(2) ] / -2(12)(13) CosA = [ 25 - 144 -169] / -312 CosA = [ -288[/-312 CosA = 288/312 A = Cos^(-1) [288/312] A = 22.61986495.... degrees.


If triangle DEF is rotated 180 degrees clockwise around the origin what will be the coordinates of point E in the image D (-13) E (31) and F (2-2)?

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Related Questions

Is a triangle with an interior angle of 67.38013505 degrees and a side of 12 cm opposite to it a right angle triangle?

Yes because 12 divided by tan(67.38013505) equals 5 And: 122+52 = 169 making the hypotenuse of the right angle triangle 13 cm


What is the sin of angle A 5 13 12?

The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees


What is the tan of angle A bc equals 5 ca equals 12 ba equals 13?

tan(23) = 1.58815308


Does 51213 form a right angle?

As given 51213 is just a number. However, a triangle with sides 5, 12, & 13, forms a classic Pythagorean right angled triangle.


Do 5 12 13 form a right angled triangle?

Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared


Would dimensions of 5 12 and 13 form a right triangle?

Yes, because they comply with Pythagoras' theorem for a right angle triangle.


How does 5 12 13 make a right angle?

By Pythagorean theorem, if the sum of squares of smaller sides of a triangle equals the square of longest side, it is a right angle triangle where the long side is the hypotenuse. 5 squared plus 12 squared is equal to 13 squared


Can a scalene triangle have a right angle?

No because otherwise it would be a right angle triangle.


Can 12 13 and 18 be lengths of the sides of a right angle triangle?

No because they don't comply with Pythagoras' theorem.


If hf is 13 fg is 5 and hg is 12 what would the tangent ratio be for angle f?

Tan(f) = HG/FG = 12/5 = 2.4


What is the cos of angle a 5 13 12?

It is: cos = adj/hyp and the acute angles for the given right angle triangle are 67.38 degrees and 22.62 degrees


What Angle A of triangle SAM is a right angle. If SM 13 mm and MA 12 mm determine the length of segment SA.?

If the right angle is at A then SA = 5 mm.