Let the middle one be n, then:
(n - 2)(n + 2) = 3n + 6
→ n² - 4 = 3n + 6
→ n² - 3n - 10 = 0
→ (n + 2)(n - 5) = 0
→ n = -2 or 5
-2 can be discounted as n is odd
→ n = 5
→ largest of the three odd numbers is 5 + 2 = 7.
-1
56.25% is not an integer and so cannot be expressed as a sum, difference, product or quotient of consecutive integers.
Yes, the integers are 12 and 13.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
The integers are 5 and 7.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
One possible answer is -4 and -3.
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
9240 is the product of the three consecutive integers 20, 21, and 22.
10-11-12