0000, 0009, 0090, 0099, 0900, 0909, 0990, 0999, 9000, 9009, 9090, 9099, 9900, 9909, 9990, 9999
90
7
Oh, dude, you're making me do math now? Alright, so if you have three numbers and you're asking how many combinations you can make with those three numbers, it's like a little math puzzle. Each number can be used multiple times, so it's like a little party for those numbers. The total number of combinations you can make with three numbers is 27. That's like having 27 different outfits to choose from for a night out, but with numbers.
You can create several different numbers from the digits 1, 3, 4, and 6 in 1346. If you consider all possible combinations of these four digits, you can form a total of 24 unique four-digit numbers (4! = 24). Additionally, you can also create various three-digit, two-digit, and one-digit numbers, which would increase the total count significantly. However, counting all permutations of all possible lengths gives a comprehensive view of the total combinations.
The number of possible 3 digit combinations you can make out of 1-9 with outrepeated digits is:9C3 = 9!/(3!(9-3)!) = 84
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
Oh, dude, you're hitting me with the math questions, huh? Alright, so to find the number of 5-digit combinations from 1 to 20, you just do 20^5, which is like 3,200,000. So, yeah, there are 3,200,000 possible 5-digit combinations from 1 to 20.
The four-digit numbers that can be formed using the digits 6, 7, 8, and 9, without repetition, are all the permutations of these four digits. There are 24 possible combinations, including numbers like 6789, 6798, 6879, and so on. Essentially, any arrangement of these four digits constitutes a valid four-digit number.
Oh, dude, let me break it down for you. So, to find the number of 5-digit combinations from 1 to 60, you just do 60 minus 1 plus 1, which gives you 60. So, there are like 60 different 5-digit number combinations you can make from that range. Easy peasy, lemon squeezy!
There are 5*4*3*2 = 120 such numbers.
4578, 4758, 5478, 5748, 5874, 5784, 7584, 7854, 7458, 7548, 8754, 8574
Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.