If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
There are 1 million possible combinations. Just think of it as a sequence of numbers, starting at 000000, 000001... all the way to 999999.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
There are 840 4-digit combinations without repeating any digit in the combinations.
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There are 360 of them.
1,000,000. Specifically, they are all numbers from 000000-999999
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
There are twelve possible solutions using the rule you stated.
9
-8