The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?
There are 25 = 32 possible outcomes.
2*2*2*2 = 16
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are 26 = 64 possible outcomes.
I believe there would be 11 possible outcomes!
There are 25 = 32 possible outcomes.
9
18 outcomes
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
24 possible outcomes.
32
There are eight (8).