There are 2 outcomes for the dime (H or T), 2 for the penny (H or T) and 6 for the die (1,2,3,4,5,6). In all, there are 2*2*6 = 24 outcomes. Some of them are given below in the pattern: dime, penny, die. The rest are easy to generate.
[H,H,1], [H,H,2], ... , [H,H,6],
[H,T,1], [H,T,2], ...
[T,H,1], ...
[T,T,1], ...
simply 10 x 2 so 20
There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.
There are 25 = 32 possible outcomes.
Th dice have 6 sides and each side have one number from 1-6 so that there are 6 possible outcomes if you rolled the dice
The total number of outcomes is 2^5 = 32.
24 possible outcomes.
simply 10 x 2 so 20
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.
There are 26 = 64 possible outcomes.
I believe there would be 11 possible outcomes!
There are 25 = 32 possible outcomes.
Th dice have 6 sides and each side have one number from 1-6 so that there are 6 possible outcomes if you rolled the dice
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
9
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
18 outcomes