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write two numbers that have the given absolute value.
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∙ 14y ago
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How do you factor 12x2-3x2?
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
Factor this polynomial completely 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
3x2 - 2x - 8?
(3x + 4)(x - 2)
What are the factors of this quadratic trinomial 3x2 -11x -4?
(3x + 1)(x - 4)
What is the factorization of this trinomial -3x2 10x-8?
-(3x - 4)(x - 2)
How do you rearrange this equation. 4-x-3x² to get the 3x² by itself?
It is not an equation it is an expression but if it was in the form of 4-x-3x2 = 0 then 3x2 by itself:- 3x2 = 4 -x
How do you factor 12x2-3x2?
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
What are the factors of the quadratic trinomial 3x2-7x plus 4?
3x2-7x+4 = (3x-4)(x-1) when factored
Simplify 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
What is 3x2-7x-20 factored?
3x2 - 7x - 20 = (3x + 5)(x - 4)
How is the graph of f(x)-3x2-4 different from the graph of f(x)-3x2?
The second graph is shifted upwards by 4 units.
Factor this polynomial completely 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
What term is canceled out in the problem 3xx plus 4 2x plus 4?
If it is 3x2 + 4 = 2x + 4, then you can subtract 4 from both sides, and get 3x2 = 2x, and then x = 2/3
Are 3x2 plus 4 and 6x2 inverses?
No.
3x2 - 4x - 4 binomials?
3x2-4x-4=0 (3x+2)(x-2)+0 x=-3/2, 2
Do solutions to systems of linear inequalities need to satisfy linear inequalities?
No. For example, the solution to x ≤ 4 and x ≥ 4 is x = 4.
Which equals 3x2 - 10x - 8 when factored completely?
3x2 - 10x - 8 = (3x + 2) (x - 4)
