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(3x + 4)(x - 2)
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∙ 12y ago
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Factor this polynomial completely 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
What is the factorization of this trinomial -3x2 10x-8?
-(3x - 4)(x - 2)
What is a correct factorization of this trinomial-3x2-10x-8?
It is: (-3x-4)(x+2) when factored
How do you factor 12x2-3x2?
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
What is 4x plus 2y equals -8 written in slope-intercept form?
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
Simplify 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
What is the name of this function 4y plus 8 equal to 3x to the power of 2 minus 2x plus 1?
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
Factor this polynomial completely 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
What is the solution to 3x squared -2x-8?
3x2-2x-8 = (3x+4)(x-2) when factored
How do you solve 3x squared plus 2x equals 16?
3x2 + 2x = 16 ∴ 3x2 + 2x - 16 = 0 ∴ 3x2 - 6x + 8x - 16 = 0 ∴ 3x(x - 2) + 8(x - 2) = 0 ∴ (3x + 8)(x - 2) = 0 ∴ x ∈ {-8/3, 2}
What is 3x squared plus 2x minus 8 equals 0?
3x2 + 2x - 8 = 0 is a quadratic equation.
Find the derivative of fxx3-4xe-2x?
if: f(x) = x3 - 4xe-2x Then: f'(x) = 3x2 - [ 4e-2x + 2(4x / -2x) ] = 3x2 - 4e-2x + 4
Expand the brackets openbracket 3x plus 4 closebracket openbracket x-2 closebracket?
(3x+4)(x-2) 3x2 -6x+4x-8 3x2-2x-8
What is the derivative of 3x2-2x?
-2
How do you factor 3x2-2x-21?
3x2-2x-21 = (3x+7)(x-3)
How do you factor 6x - 6x -16?
6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
How do you factor 3x2 plus 2x -21?
3x2 + 2x - 21 = (3x - 7) (x + 3)
