The given sequence is an arithmetic progression.
a = first term of A.P. = 10, d = common difference = an - an-1 = -4
nth term of an A.P. is given by: an = a+(n-1)d
Plugging in the values we get an = 10+(n-1)(-4) = 10 - 4n + 4 = 14 - 4n.
It is: nth term = -4n+14
The nth term is (2n - 12).
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
10 - 4n
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
It is: nth term = -4n+14
The nth term is (2n - 12).
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
10 - 4n
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
Un = 2n + 2 is one possible answer.
The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 9n-2