The given sequence is an arithmetic progression.
a = first term of A.P. = 10, d = common difference = an - an-1 = -4
nth term of an A.P. is given by: an = a+(n-1)d
Plugging in the values we get an = 10+(n-1)(-4) = 10 - 4n + 4 = 14 - 4n.
It is: nth term = -4n+14
The nth term is (2n - 12).
nth term= 6 + (n-1) (2)
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: 26-8n
It is: nth term = -4n+14
The nth term is (2n - 12).
nth term= 6 + (n-1) (2)
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: 26-8n
10 - 4n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
Tn = 10 + n2
Un = 2n + 2 is one possible answer.
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 9n-2
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)