Q: Are graphed linear inequalities supposed to be shaded?

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Graph both inequalities and the area shaded by both is the set of answers.

true

overlap

The answer depends on which area is shaded for each inequality. I always teach pupils to shade the unwanted or non-feasible region. That way the solution is in the unshaded area. This is much easier to identify than do distinguish between a region which is shaded three times and another which is shaded four times.

the feasible region is where two or more inequalities are shaded in the same place

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It represents the solution set.

Graph both inequalities and the area shaded by both is the set of answers.

overlap

true

The answer depends on which area is shaded for each inequality. I always teach pupils to shade the unwanted or non-feasible region. That way the solution is in the unshaded area. This is much easier to identify than do distinguish between a region which is shaded three times and another which is shaded four times.

the feasible region is where two or more inequalities are shaded in the same place

The answer depends onwhether or not the lines represent strict inequalities,what the shaded area represents.

Actually, a linear inequality, such as y > 2x - 1, -3x + 2y < 9, or y > 2 is shaded, not a linear equation.The shaded region on the graph implies that any number in the shaded region is a solution to the inequality. For example when graphing y > 2, all values greater than 2 are solutions to the inequality; therefore, the area above the broken line at y>2 is shaded. Note that when graphing ">" or "=" or "

The answer depends on which area is shaded for each inequality. I always teach pupils to shade the unwanted or non-feasible region. That way the solution is in the unshaded area. This is much easier to identify than do distinguish between a region which is shaded three times and another which is shaded four times.

plane

it is called a half plane :)

Graph as though the inequality is an equality. Then, find a point on one side of the line and see if it makes the inequality true. If it is true then that side gets shaded.