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Q: Can a number be divisible by 9 and 3?

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If a number is not divisible by 3 then it is not divisible by 9.

A prime number is not divisible by any numbers except 1 and itself. A composite number is divisible by other numbers. 9 is divisible by 3, so it is a composite number.

Yes, every number that's divisible by 9 is divisible by 3

To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

None, because 9 is divisible by 3.

There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?

3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.

9 is divisible by 1, 3 and 9.

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

Yes. If the sum of a number's digits add up to 3 (or a multiple of 3) then the number is divisible by 3. 5 + 3 + 1 = 9 : as 9 is a multiple of 3 then 531 is divisible by 3 (177 x 3 = 531). NOTE : A similar process applies to identify if a number is divisible by 9. If the sum of the number's digits add up to 9 (or a multiple of 9) then the number is divisible by 9. 5 + 3 + 1 = 9 : 531 = 59 x 9.

Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.

No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6

No. To check divisibility by nine, sum the digits. If they add up to 9 (or a multiple of 9) then the number is divisible by 9. This trick works for 9 divisibility and 3 divisibility. In this problem: 3 + 0 + 9 + 1 = 13, which is not divisible by 9. Suppose the number was 3591: 3+5+9+1=18, which is divisible by 9 (you can check 1+8=9). You can keep summing the digits of the new numbers till you get to a number which is either 9 or some other number. (If it's 3 or 6, then the number is divisible by 3)

That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.

Not always because 33 is divisible by 3 but not by 9

The smallest number divisible by 3 6 and 9 is 18.

36360 is a 5 digit number that is divisible by both 3 and 9.

Except for zero, any number can divide into any other number. If the answer is a whole number, the larger number is said to be divisible by the smaller. 9 divided by 4 = 2.25 9 is not divisible by 4. 9 divided by 3 = 3 9 is divisible by 3.

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.

NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)

9101997 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 9 + 1 + 0 + 1 + 9 + 9 + 7 = 36, which is divisible by 3. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 9101997 is a composite number.

yes, you know that because if you add the digits together and that number is divisible by 9, then that large number is divisible by 9. 3+4+2 is 9, which is divisible by 9. conclusion 342 is divisible by 9.

Because 9 is a multiple of 3.

9 is a compostie number because it is divisible by 3. A prime number is only divisible by 1 and itself.