No,for example, a 1x2 rectangle has an area of 2 but a perimeter of 6
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
If both numbers are even, it will always be an even number. For example, 2 + 2 = 4.
To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
The perimeter of a rectangle is always even because the perimeter is twice the length plus twice the width. Whenever you multiply a number by 2, the product is even. When you add two even numbers the sum is even.
No. A rectangle of 1 x 3 has the same perimeter as a rectangle of 2 x 2, but the areas are different.
a parallelogram is always a example of a rectangle a rhombuz and a trapezoid
A rectangle is always a quadrilateral and a parallelogram.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
No, any shape with four sides and same perimeter will always be a square.
Area is length times width (only for rectangle) while perimeter is all the sides added up (always).
Not always because a 2 by 12 rectangle will have the same area as a 4 by 6 rectangle but they both will have different perimeters.
no because one rectangle may be 3x4 which the perimeter is 14 and one rectangle may be 5x2 which as well equals 14
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
Sometimes. Experiment with a small square and with a large square (though any shape rectangle will do). A square of 4 x 4 has a perimeter of 16, and an area of 16. A smaller square has more perimeter than area. A larger square has more area than perimeter.
A quadrilateral shape
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
Nearly always multiply. However, for the perimeter of a rectangle, you add the length + width + length + width. This is even simplified by multiplying the length and the width by 2
A quadrilateral, a parallelogram, a rhombus, a rectangle, a regular polygon.
130/4 (4 sides to a rectangle)= 32.5 32.5*32.5=1065.25 square meters (because the largest area of a rectangle is always a ^ ^ square). length width
A quadrilateral polygon
Perimeter is a unit of length. Area is a unit of area. The two units are not directly convertible.However, the area of a rectangle is length times width, and the perimeter is two times length plus two times width. Given constant perimeter, a square has maximum area, while a very thin rectangle has nearly zero area. (In calculus terms, the limit of the area as length or width goes to zero is zero.)Depending on how you want to name your units, you can always find a rectangle whose perimeter is "larger" than area, but this is a numerical trick that is not valid in any school of thought of mathematics that I know.
All we can tell is length plus width is 606.5 ...(always assuming you're talking about a rectangle)
It can be infinitely large. Consider a rectangle of length A cm where A â‰¥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.