10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
5xy (2x - 3y + 4 )
x2 + 13x + 36 = (x + 9)(x + 4)
5x(3x + 1)
4(t + 3)(t2 - 3t + 9)
It can't be factored because its discriminant is less than zero.
(5x - 4)(2x + 3)
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
28w2 + 196wd + 343d2 = 7(2w + 7d)2.
10x2 + 101x + 10 = (10x + 1)(x + 10)
If that's - 94x, the answer is 2(3x - 10)(x2 + 5x + 1)
4x3+10x2+2x+5= (2x+5)(2x2+1)
The answer is 21
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
Given: x4 + 3x3 - 10x2 = 0 You can start by dividing both sides of the equation by x2: x2 + 3x - 10 = 0 Then factor out the left side of the equation into simpler terms: (x + 5)(x - 2) = 0 For the result to be 0, either of the terms in brackets on the left must equal 0, so that means there are two answers: x = -5, x = 2
10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)