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How do you solve 3x (x-2)-7?
6x2=-7
What does 6x squared plus 35xy plus 11y squared equal?
6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y)
2 5x plus 1 equals 3 3x plus 7 what is x?
25x+1=33x+7 25x=33x+6 -8x=6 x=-8/6 x=-4/3
Which of the binomial below is a factor of this trinomial 6x2-5x-25?
6x2-5x-25 = (3x+5)(2x-5) when factored
How do you solve 6x3-6x2-12x equals 0?
6*3-6*2-12x v v 18 - 12-12x v v 6-24x -6 -6 something like that..
How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?
3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11
How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
What are the ratings and certificates for 33X Around the Sun - 2005?
33X Around the Sun - 2005 is rated/received certificates of: UK:15
How do you solve 3x (x-2)-7?
6x2=-7
How do you solve or factor 5x squared plus 33x plus 18?
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5
Negative three open bracket two x plus oneclose bracket open bracket four plus three x close bracke?
-3(2x + 1)(4 + 3x) = -3[8x + 6x2 + 4 + 3x] = -3[6x2 + 11x + 4] = -18x2 - 33x - 12.
What are the first 15 multiples of 6?
They are 6x1, 6x2, 6x3 and so on until 6x15.They are 6x1, 6x2, 6x3 and so on until 6x15.They are 6x1, 6x2, 6x3 and so on until 6x15.They are 6x1, 6x2, 6x3 and so on until 6x15.
How do you solve this math problem 33x-47?
80
What is the solution to 33x plus 9 18?
33x + 9 = 18 ----> 33x = 9 ----> x = 3/11
What is (6x2) plus 3?
(6 × 2) + 3 = 15
How do you do this problem 12x 33x x 92- 12 x?
(12)(33x)(92-12x) (12)(33x)(92)-(12)(33x)(12x) 36432x-4752x2 if this restatement of the grouping in the original problem is correct.
What is the solution set for 6x2-x-15 equals 0?
6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as: [(6x + 9)/3][6x - 10)/2] = 0 (2x + 3)(3x - 5) = 0 let each factor be zero: 2x + 3 = 0 or 3x - 5 = 0 solve for x: The solutions are: x = -3/2 and x = 5/3
