6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as:
[(6x + 9)/3][6x - 10)/2] = 0
(2x + 3)(3x - 5) = 0 let each factor be zero:
2x + 3 = 0 or 3x - 5 = 0 solve for x:
The solutions are: x = -3/2 and x = 5/3
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'x' must be zero, so the solution set is [ 0 ].
4a + 6 - 4a = -10 Combining like terms: 6 = -10 or 4 = 0 which is FALSE. So the solution set is empty.
It has infinitely many solutions.
Yes.
50x squared equals 20x-2 equals zero is not possible, for 20x-2 = 0 --> x = 1/10 While 50x2 = 0 means that x should be zero. So either 50x2 =/ 20x-2 or 20x-2 =/ 0