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There is no one digit number that is wholly divisible by 4 and 9. * * * * * Unless you consider 0.
No. Consider 13 or 23.
108 -999, if you consider negative numbers.
If you consider whole numbers, the largest 5 digit number with repetition is 99999 the smallest 4 digit number without repetition is -9876 Their difference is 99999 - (-9876) = 99999 + 9876 = 109875.
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?
There is no one digit number that is wholly divisible by 4 and 9. * * * * * Unless you consider 0.
No. Consider 13 or 23.
99 is. But if you want to get fancy, you might consider 99 .
108 -999, if you consider negative numbers.
If you consider whole numbers, the largest 5 digit number with repetition is 99999 the smallest 4 digit number without repetition is -9876 Their difference is 99999 - (-9876) = 99999 + 9876 = 109875.
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
The square of 8, which is 64 and the square of 9 is 81. Once you consider the square of 10, it is 100 so it is no longer a two digit number.
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?
The short answer is 1000. This is very easy to visualise: Simply consider each number in the combination to be a digit in a decimal number. We then end up with a three-digit number. Such a three-digit number ranges in value from 000 to 999, or 1000 unique combinations.
I need a lil help
Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
Divide the two-digit number by the one-digit number. If the remainder is zero then the 2-digit number is a multiple and if not, it is not.