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Q: Diagonal measure of 28ft x 28ft square?

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The answer is 560 ft2.

20ft x 28ft = 560ft2

28ft = 853.44cm = 8.5344mtr 10ft = 304.8cm = 3.048mtr 8.5344 x 3.048 = 26.013 sq mtr

The diagonal of a 30' x 30' square is: 42.43 feet.

Multiply width by length to get the area. The answer would be 308 square feet.

The diagonal measurement of an 18 x 18 square is: 25.46 units.

A 12" x 12" square has a diagonal measurement of: 16.97 inches.

The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)

The diagonal of a 46' x 46' square is 65.05 feet.

Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.

Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.

The diagonal of a 36 x 36 foot square is 50.91 feet.

The diagonal of the paver is about 848.53mm

A square has 4 sides of equal length (say x). The diagonal length = x * (2)^0.5 = 1.414x, from Pythagorus's theorem. So, dividing the diagonal length by the square root of 2 will be the answer.

10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet

Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 20 × √2 ≈ 28.3 units

A diagonal of a square measures: Side X sqrt(2).Approximately (8 cm) X (1.414) = 11.312 cm

The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.

Diagonal = sqrt (twice the square of a side) eg: square of side 8 units, d = sqrt(2 x 64) = sqrt 128 = 11.3137

About 28.28 feet.

2.8284 feet

d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)

By using Pythagoras: diagonal2 = side2 + side2 = side2 x 2 => diagonal = side x √2

There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13

Assuming you mean 28ft x 28ft x 6ft you would need 174 2/9 yards of concrete, assuming no waste.