Use Pythagoras:
Diagonal² = √(2 × sidelength²)
→ diagonal = side_length × √2
→ diagonal = 20 × √2 ≈ 28.3 units
About 28.28 feet.
Using Pythagoras' theorem it is 20 times the sq rt of 2
The diagonal of a 46' x 46' square is 65.05 feet.
By using Pythagoras: diagonal2 = side2 + side2 = side2 x 2 => diagonal = side x √2
53.85164807' by means of Pythagoras.
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
Using Pythagoras it is 20 times square root of 2
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
About 28.28 feet.
Using Pythagoras' theorem it is 20 times the sq rt of 2
The diagonal of a 30' x 30' square is: 42.43 feet.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the length of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 12 x 16 rectangle can be calculated as follows: diagonal = √(12^2 + 16^2) = √(144 + 256) = √400 = 20. Therefore, the diagonal measurement of a 12 x 16 rectangle is 20 units.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
The diagonal of a 46' x 46' square is 65.05 feet.
The diagonal is 15.652'