About 28.28 feet.
Using Pythagoras' theorem it is 20 times the sq rt of 2
The diagonal of a 46' x 46' square is 65.05 feet.
By using Pythagoras: diagonal2 = side2 + side2 = side2 x 2 => diagonal = side x √2
53.85164807' by means of Pythagoras.
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
Using Pythagoras it is 20 times square root of 2
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
About 28.28 feet.
Using Pythagoras' theorem it is 20 times the sq rt of 2
The diagonal of a 30' x 30' square is: 42.43 feet.
Oh, dude, you're asking me to bust out some high school math here. So, like, to find the diagonal of a rectangle, you use the Pythagorean theorem. It's like a^2 + b^2 = c^2, where a and b are the sides of the rectangle. In this case, it's 12^2 + 16^2 = c^2. So, the diagonal would be the square root of 400, which is 20.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
The diagonal of a 46' x 46' square is 65.05 feet.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
The diagonal is 15.652'