x2-9x can be factored by taking x out of each term
x(x-9)
If you are looking for the zeros of this function: x = -2 plus or minus 2 X the square root of 5.
x equals negative b plus or minus the square root of b squared minus 4bc over 2a
-cos2(x)1 = sin2(x) +cos2(x)1 - cos2(x) = sin2(x)-cos2(x) = sin2(x) - 1
6 squared = 3 squared + x squared if x is the height (altitude) of the triangle 36 = 9+x squared x squared =27 so x = 3 sqrt3 = 5.19615
This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 15, which is 30. Then you need to find the factors of thirty, i.e. 3 and 10, 15 and 2, 5 and 6. You need to find the pair of factors that add to make -13x, which would be -3 and -10. you then need to put these into the equation - it would become 2x squared -10x (as one equation) and -3x +15 would be another equation. we can see that 2x squared and -10x have 2x in common, and so the answer for that would be 2x (x - 5). the second equation would be -3 (x - 5). the two equations have x - 5 in common, and that would make up the first set of brackets. you then add the rest (2x - 3) and your answer would be (x - 5) (2x - 3).
(x + 12)(x - 3)
(9x + 8)(9x - 8)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
x2-9x+8=0 has two solutions:x = 8x = 1
(x + 2)(3x - 1)(3x + 1)
x2 - 9x + 20 = (x - 4)( x - 5)
It is: (x-2)(x-7) when factored
5x2 + 9x + 13 has no real factors.
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
x2 - 9x + 8 = (x-1)(x-8)
x = -2/3,7/6
-9(x + 8)