You need to factor the following trinomial:
x2 + 2x - 15
In other words, you want to find an expression in this form, which is equal to the trinomial:
(A + B)(C + D)
Finding the values for A, B, C, and D is mostly a trial-and-error process, but here are a few tips that are helpful for situations such as this:
Since A times C equals x2, we know that we have something like this:
(x + B)(x + D)
Now, we also know that -3 times 5 is -15, and -3 plus 5 is 2. So, we have found the following:
(x - 3)(x + 5)
You can use the FOIL pattern (multiply the First numbers, then the Outside, Inside, and Last numbers and add together) to check that this factorization is correct:
(x - 3)(x + 5)
= AC + AD + BC + BD
= x2 + 5x - 3x - 15
= x2 + 2x - 15
It looks like that's the right answer. So, the factorization of this trinomial is (x - 3)(x + 5).
(3x - y)(3x - 5y) and (2x + 1)(2x + 11)
factor the trinomial 16x^2+24x+9
10 + 9x
vbh
x2-5x+4 = (x-1)(x-4) when factord
(x + 3)(x - 2)
(x + 5)(x - 3)
-((x + 2)(x - 9))
5(n2 + 2n + 4)
(3x+1)(x+2)
(x + 15)(x + 5)
(x + 10)(x + 3)